The output of command line utility ./Utility -P consist of two rows of text.
I use shell script to capture standard output from this sub shell and show it as notification use zenity:
#!/bin/bash
output="$( ./Utility -P )"
zenity --info --text "${output}" --title "Job done"
The only the second row matters, so I need show only 2nd row from the utility output. Now I can pipe only 2nd row for further processing in above shell script?
I'm considering use awk sample:
awk -F: 'NR==2 {print $1}' filename
How to connect this sample to above shell code?
awk -F: 'NR==2 {print $1}' filename? If you want the whole second line,awk 'NR==2 {print}' filename=>output=$(./Utility -P | awk 'NR==2 {print}'), however for this task you could use justsed:output=$(./Utility -P | sed -n '2p')output="$( ./Utility -P | awk 'NR==2 {print}')"var=something: unix.stackexchange.com/a/599170/114435sed:output=$(./Utility -P | sed -En '2s/.*?(.{10})$/\1/p')(this will remove everything but the last 10 characters on line 2, regardless of the characters, I think it's ok? Otherwise if you want to avoid printing in case one of the last ten characters is something other than a letter or a digit:output=$(./Utility -P | sed -En '2s/.*?([A-Za-z0-9]{10})$/\1/p'))Utilitything? Is it printing using Windows-style line-endings (\r\n)? Try./Utility -P | tr -d '\r' | sed -En '2s/.*?(.{10})$/\1/p'. If it works, you have carriage returns in your line endings.